bagdb2200
+1y
---------------------------------------------Originally posted by BioMaxThe other thread got me thinking about doing an entire tech piece on this subject, but I wouldn't even know where to start. From the simplest standpoint both diagrams are 1:1 leverage ratios, just for different drive angles. In the first pic, if the force is pushing up on the left side then the right side will move down an equal distance and force, but what happens when diagram two is pushed up? The lower point would move to the left an equal distance and force. So what if the left side of the first diagram had a rod attached to it that was driven by an A-arm? The rod would not push directly against the lever at a consistent 90o angle, so the ratio would then change and because the rod would be following the path of the a-arm at the bottom and the path of the lever at the top, the "driven" leverage ratio would be constantly changing. This would also be the case on the opposite side of the lever, constanly changing based on the angle(s) of the "driving" and "driven" parts. The shorter the parts, the more drastic the angle change, thus the more inconsistent the leverage ratios. Are we completely confused yet?---------------------------------------------That's why when I draw out "canti" arm setups I find the complete arc the arm will travel, then setup so that halfway through that arc it's perpindicular to the direction of travel. That way you don't lose any linear lift to the circular path. You will still have the slight change in leverage for the force though, it's unavoidable when travelling through an arc.