granth
+1y
"If you take that angle and plug it into your spindle/balljoint relationship you will end up with something like what is shown in diagram 2. The center tierod points are moved back because the steering arm on the spindle is closer to the center of the vehicle. the angles Aew and Bfy are equal to Aef and Bfe. If it were a rear steer it would be the same for the involved angles. If the steering arm on the spindle was further out from the center (on a front steer) then the original diagram, then the center tierod points would be further foward in order to keep with our figured angle from the original ackerman diagram."
I understand your first post up until this point, probably because I have no "parts" in front of me. The way to get your angle s from your lower ball joint, to your tie rod, to the center line of the vehicle, or rear end, whatever. Just for the sake of asking, this is given your rear end has the pumpkin centered correct? its more or less the center of the vehicle that you are measuring to?
You say to "plug in your angle to the balljoint/spindle relation, but what exactly does that mean? What are you doing with the 80 degrees, as you used in your example? Also, when you go to set your inner tie rod placement, will it not be the same on both sides? I am guessing when you figure out the whole balljoint/spindle deal with your newly found angle, this sets where your inner tie rod mounts should be, correct? So I guess my main question is what exactly are you doing with that number?
Does this hold true with rack and pinion as well?